(2x^2+7)6=(x^2+1)15

Solution for (2x^2+7)6=(x^2+1)15 equation:

Simplifying
(2x2 + 7) * 6 = (x2 + 1) * 15

Reorder the terms:
(7 + 2x2) * 6 = (x2 + 1) * 15

Reorder the terms for easier multiplication:
6(7 + 2x2) = (x2 + 1) * 15
(7 * 6 + 2x2 * 6) = (x2 + 1) * 15
(42 + 12x2) = (x2 + 1) * 15

Reorder the terms:
42 + 12x2 = (1 + x2) * 15

Reorder the terms for easier multiplication:
42 + 12x2 = 15(1 + x2)
42 + 12x2 = (1 * 15 + x2 * 15)
42 + 12x2 = (15 + 15x2)

Solving
42 + 12x2 = 15 + 15x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-15x2' to each side of the equation.
42 + 12x2 + -15x2 = 15 + 15x2 + -15x2

Combine like terms: 12x2 + -15x2 = -3x2
42 + -3x2 = 15 + 15x2 + -15x2

Combine like terms: 15x2 + -15x2 = 0
42 + -3x2 = 15 + 0
42 + -3x2 = 15

Add '-42' to each side of the equation.
42 + -42 + -3x2 = 15 + -42

Combine like terms: 42 + -42 = 0
0 + -3x2 = 15 + -42
-3x2 = 15 + -42

Combine like terms: 15 + -42 = -27
-3x2 = -27

Divide each side by '-3'.
x2 = 9

Simplifying
x2 = 9

Take the square root of each side:
x = {-3, 3}